What is distance covered by a freely falling body during the first three seconds of its motion ?
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Answer:
The first equation shows that, after one second, an object will have fallen a distance of 1/2 × 9.8 × 12 = 4.9 m. After two seconds it will have fallen 1/2 × 9.8 × 22 = 19.6 m; and so on.
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