Physics, asked by sanchita35743, 7 months ago

what is distance travelled by an object from t=0 to t=10s in the following graph?
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Answers

Answered by shaikfahad3210
13

Answer:

50 metres.

Explanation:

We know that v = s/t

If s and t are very small v can be written as v = ds/dt.

From it ds = vdt.

To find s from t = 0 s to t = 10 s you need to integrate the above expression. So we need to find the area made by the curve in between 0 s to 10s with speed as y-axis and time as x-axis. If you want know how this happens read below. But believe me, it will mess up your mind if you are studying 11th class or below standards.

{ The basic idea of integrating a curve is to divide into small segments and to form rectangles by drawing perpendicular lines to  the ends of this segment to x axis. This is called Riemann sum. See the image below, you will understand it better}

We can see a  right-triangle from 0 s to 10 s in the graph, of base 10 and height 10.

So its area is 1/2 x 10 x 10 = 50.   ( Area of a triangle is 1/2 base x height)

So the object travels a distance of 50 m in 0 s to 10 s.

↓↓↓Riemann sum↓↓↓

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Answered by manjubala39
13

Hope it helps you ☺️☺️

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