Question

what is distance when time is 5 sec acceleration is 4 ms square initial velocity is 20 m/s and final velocity is 40 m/s​

Answer 1

Given data : Time is 5 sec, acceleration is 4 m/s², initial velocity is 20 m/s and final velocity is 40 m/s.

To find : The distance ?

Solution : Now, we use kinematical equation

⟹ s = u * t + ½ * a * t²

{ Where,

• v = final velocity
• u = initial velocity
• a = acceleration
• t = time taken by particle
• s = distance covered by particle }

Now, by formula

⟹ s = u * t + ½ * a * t²

⟹ s = 20 * 5 + ½ * 4 * 5²

⟹ s = 40 + ½ * 4 * 25

⟹ s = 40 + 2 * 25

⟹ s = 40 + 50

⟹ s = 90 m

Answer : Hence, the distance is 90 m.

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