Question

what is dy/dx of y to the ower x + x to the power y is equal to 1​

Answer 1

Answer:

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Step-by-step explanation:

yˣ + x^y = 1

x logy + y logx = log 1

differentiating

x * 1/y * y' + logy    +     y/x - logx * y' = 0

x * 1/y * y' + logy    =   -  y/x - logx * y'

logy    =     - y/x - logx * y'   -    x * 1/y * y'

y' (-y/x - logx - x/y ) = log y

y' =  logy / (y/x + logx + x/y )