Question

What is EAN of Nessler's Reagent is K2[HgI4]?

Answer 1

Answer:

K2[Hgl4]

EAN = 80-2+8

= 86

which is equal to the Noble gas Radon (Rd).

Answer 2

EAN of Nessler's Reagent is$K2[HgI4]$ is 86

Explanation:

• Nessler's Reagent is $K2[HgI4]$ in an alkaline medium like$NaOH or KOH.$
• In order to find out the oxidation number of Hg,
• Let  it's oxidation number to be x. Now, consider the compound as anion and cation-$K+$ and $[HgI4]2-$
• In the complex, iodine $[HgI4]2-$ has an oxidation state of$-1$.
• So,the total sum of oxidation number of Hg and I should be equal $-2$.
• $x-4=-2$
• $x=-2+4=2$
• Thus, Mercury has an oxidation number of $+2$ in Nessler's Reagent .
• Effective atomic number (EAN), is the number that represents the total number of electrons which is surrounding the nucleus of a metal atom in a metal complex.
• The Chemical name of $K2[HgI4]$ Nessler's reagent.
• It's IUPAC name is potassium tetraiodo mercurate(II)
• $EAN = (z - x) + (C.N. * 2)$
• $EAN = 80-2+8.$
• $EAN =86$