Question

what is effective area of half wave dipole operating at 1GHz

Answer 1

Answer:

given that,

Frequency f = 500 mhz

We know that, the directivity of the half wave dipole antenna is 1.64

The effective area of an antenna is given by

A_{e} = \dfrac{\lambda^{2}}{4\pi}DA

e

=

4π

λ

2

D

Now, the wave length is

\lambda =\dfrac{c}{f}λ=

f

c

\lambda =\dfrac{3\times10^{8}}{500\times10^{6}}λ=

500×10

6

3×10

8

\lambda = 0.6 mλ=0.6m

Now, the effective area

A_{e} = \dfrac{\lambda^{2}}{4\pi}DA

e

=

4π

λ

2

D

put the value in the formula

A_{e} = \dfrac{(0.6)^{2}}{4\pi }\times1.64A

e

=

4π

(0.6)

2

×1.64

A_{e} = 0.047\ m^{2}A

e

=0.047 m

2