What is efficiency of heat engine working between 327°c and 27°c ?
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Answered by
5
Answer:
Explanation:
Efficiency (eta) is given in terms of both temperature and heat that is :
Eta = 1 - (T2/T1) = 1 - (Q2/Q1)
Where subscript 1 stands for source and 2 for sink.
Temperature has fundamental unit as Kelvin so you need to convert °C to K.
T1 = 327 + 273 = 600 K
T2 = 27 + 273 = 300 K
Eta = 1 - (300/600) = 1 - 0.5 = 0.5 = 50%
Is it fine?^_^
woonnaamith:
i gave it quicker and i got the same answer and u gave the best answer as her's , please justify?
Answered by
5
Answer:
Efficiency (eta) is given in terms of both temperature and heat that is :
Eta = 1 - (T2/T1) = 1 - (Q2/Q1)
Where subscript 1 stands for source and 2 for sink.
Temperature has fundamental unit as Kelvin so you need to convert °C to K.
T1 = 327 + 273 = 600 K
T2 = 27 + 273 = 300 K
Eta = 1 - (300/600) = 1 - 0.5 = 0.5 = 50%
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