Question

what is electric field due to infinity sheet charged plane?

Answer 1

Hope this will help you.....

Answer 2

AnswEr:-

• $\: \bf{ E = \frac{ \sigma}{2 \epsilon _{0} } }$

Explanation:-

Refer to the attachment first ;

$\implies \:{ \sf{ \phi _{total} = \phi _{1} + \phi _{2} + \phi \: _{3}} } \\ \\ \longrightarrow \: \sf{ \int EdA cos 0 \degree + \int EdAcos0 \degree + \int EdAcos90 \degree}$

$\sf{total \: charge} \: = \sigma \times A \: \: \: \: \\ \sf{where \: \sigma = surface \: charge \: density}$

Now,

$\longrightarrow \: \tt{ \frac{Q _{inside} }{ \epsilon _{ 0}} = 2EA} \\ \\ \longrightarrow \: \tt{ \frac{ \sigma \cancel A}{ \epsilon _{0}} = 2E \cancel{A}} \\ \\ \longrightarrow \: \boxed{ \tt{ E \: = \frac{ \sigma}{2 \epsilon _{0} } }}$