Question

what is electric potential at point of distance of 4*10^10 m vaccum from positive ion​

Answer 1

Given:

Charge of 3.2 × 10^(-19) C is present.

To find:

Electrostatic potential at a distance of 4 × 10^(-10) m from the charge ?

Calculation:

The general expression for Electrostatic potential is:

$\rm V = \dfrac{q}{4\pi \epsilon_{0}r}$

• $\dfrac{1}{4\pi\epsilon_{0}}$ has a value of 9 × 10⁹.

$\rm \implies V = (9 \times {10}^{ 9} ) \times \dfrac{3.2 \times {10}^{ - 19} }{4.4 \times {10}^{ - 10} }$

$\rm \implies V = 6.54 \: volts$

$\rm \implies V \approx \: 6.2 \: volts$

So, approximately the potential becomes 6.2 Volts.