Question

What is electronic configuration of diatomic helium molecule?

Answer 1

Answer:

Helium is not a diatomic atom. It is monoatomic

Because it contains stable configuration.

Electronic Configuration: 1s2

Answer 2

$(\sigma_{1s})^2,(\sigma_{1s}^*)^2,(\sigma_{2s})^0,(\sigma_{2s}^*)^0,[(\pi_{2p_x})^0=(\pi_{2p_y})^0],(\sigma_{2p_z})^0,[(\pi_{2p_x}^*)^0=(\pi_{2p_y}^*)^0],(\sigma_{2p_z}^*)^0$

Explanation:

According to the molecular orbital theory, the general molecular orbital configuration of helium will be,

$(\sigma_{1s}),(\sigma_{1s}^*),(\sigma_{2s}),(\sigma_{2s}^*),[(\pi_{2p_x})=(\pi_{2p_y})],(\sigma_{2p_z}),[(\pi_{2p_x}^*)=(\pi_{2p_y}^*)],(\sigma_{2p_z}^*)$

As there are 2 electrons present in helium atom.

The number of electrons present in $He_2$ molecule = 2(2) = 4

The molecular orbital configuration of $He_2$molecule will be,

$(\sigma_{1s})^2,(\sigma_{1s}^*)^2,(\sigma_{2s})^0,(\sigma_{2s}^*)^0,[(\pi_{2p_x})^0=(\pi_{2p_y})^0],(\sigma_{2p_z})^0,[(\pi_{2p_x}^*)^0=(\pi_{2p_y}^*)^0],(\sigma_{2p_z}^*)^0$

Learn more about molecular configuration

https://brainly.in/question/1139099

https://brainly.in/question/1533071