what is emperical formula of an oxide of element (E) containing 40precent element by mass
Answers
Answered by
0
Answer:
EO3
40/32=1.25 ----element
60/16=3.75-------oxygen
dividing both by 1.25,
we get 1 and 3 respectively.
so empirical formula is EO3....
Plz mark as brainliest....
Explanation:
Answered by
0
Explanation:
It's not a my cup of tea so I shared the link to you
Similar questions
Accountancy,
4 months ago
History,
4 months ago
English,
4 months ago
Math,
8 months ago
Math,
1 year ago