Question

What is energy stored in condenser if capacity 3nF and across P.D 400 V?

Answer 1

Given :

Capacitance (C) = 3 nF = 3×10⁻⁹ F

Potential Difference = 400 V

To Find :

Energy stored in the condenser

Solution :

Energy stored in a charged condenser can be given as -

Energy (E) = $\frac{1}{2} CV^2$

where, C = Capacitance; V = Potential difference

∴  Energy stored in the condenser (E) = $\frac{1}{2}$ × 3 ×10⁻⁹ ×400

                                                               = 6 × 10⁻⁷ J

Therefore, the energy stored in the condenser of capacitance 3 nF is found to be 6 × 10⁻⁷ J.