Question

what is escape velocity?​

Answer 1

Answer:

The minimum velocity which a body requires to escape the gravitational force or a celestial body.

Hope it helps

Answer 2

$\huge\bf\underline\purple{Answer࿐}$

The minimum velocity with which a body should be projected from the surface of a planet so as to escape its gravitational pull is known as $\sf\pink{escape \:velocity}$ of that planet.

Let us consider a body of mass 'm' on the surface of earth of mass 'M' and radius 'R',

Gravitational potential energy (GPE) = $\sf\frac{-GMm}{R}$

If the body is given escape velocity '$\sf{V_{e}}$'.

Kinetic energy (KE) = $\sf\frac{1}{2}$m$\sf{V_{e}}^2$

Total Energy (Initial) = $\sf\frac{-GMm}{R}$ + $\frac{1}{2}$m${V_{e}}^2$

Total Energy (Final) = 0(r = $\infin$)

According to law of conservation of energy,

$\sf\frac{-GMm}{R}$ + $\sf\frac{1}{2}$m$\sf{V_{e}}^2$ = 0

$\sf\frac{1}{2}$$\sf\cancel{m}$$\sf{V_{e}}^2$ = $\sf\frac{-GM\cancel{m}}{R}$

$\sf{V_{e}}^2$= $\sf\sqrt{\frac{-2GM}{R}}$= $\sf\sqrt{2gR}$

$\large\tt\red{@AlwaysRight}$