Question

What is escape velocity obtain an expression for it

Answer 1

Answer:it is the minimum velocity with which a body must be projected vertically upward in order it may just escape the gravitational field of the earth.

Explanation:F= GMm/x**2..........1

Wd in displacing m from pto q

dw= Fdx..........2

From 1 and 2

dw = GMm/x**2 dx

On integrating x from limit infinity to R

w = - GMm( -1/R)

w= GMm/R

This work done is due to motion of body hence associated to K.E

1/2mve**2 = GMm/R

where ve is escape velocity

ve= √2GMm/R

g=GM/R**2

ve= √2gR**2/R

ve=√2gR

Hope it helps