Question

what is f'(6) if f(x)=x√2x-3​

Answer 1

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Answer 2

Concept

g(x) is said to be differentiable at the point x=a if the derivative g'(a) exists at every point in its domain if g is a real-valued function and 'a' is any point in its domain for which g is defined. The function's derivative g(x) = xⁿ is g’(x) = nx⁽ⁿ⁻¹⁾.

Given

Here, f(x) = x√2x - 3​ = √2x² - 3

Find

We have to find the value of f’(6).

Solution

Now, f’(x) = √2 * 2x - 0 = 2√2x.

So, f’(6) =  2√2 * 6 = 12√2

Therefore, we can conclude that the value of f’(6) is 12√2 .

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