What is f(x) given that f(X-1) =2x+5?
Answers
If f(x-1) = 2x+3, then what is f(x) and how did you arrive at that answer?
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Well, we know that there exists a function [math]f(x)[/math] such that [math]f(x-1)[/math] is a direct transformation of its parent function. First we want to set [math]x=x-1[/math]. Conceptually, it might be easier just to annotate one of the [math]x[/math]’s as a completely different variable, because we know that [math]x[/math] doesn’t equal [math]x-1[/math]. So let’s rewrite as [math]x=y-1[/math] and solve for [math]y[/math].
We now have [math]y=x+1[/math] where [math]y(x)[/math] is actually our parent function and [math]y(x)=f(x+1)[/math]. So take our equation [math]f(x-1)[/math] and substitute each [math]x[/math] with [math](x+1)[/math]. So
[math]\displaystyle f(x)=2(x+1) + 3[/math]
and
[math]\displaystyle f(x)= 2x + 5[/math].
We can check this by finding [math]f(x-1)[/math] because it should equal [math]2x+3:[/math]
[math]\displaystyle f(x-1)= 2(x-1) + 5[/math]
[math]\displaystyle f(x-1)= 2x + 3[/math].
Answer:
from fx we have to find the value of x and put it in equation
so fx =x-1
x=1
putting this value in 2x+5
we get 7
so final answer becomes 7
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