Question

What is formed when salicylic acid is treated with Bromine water in basic medium?

Answer 1

Initially, we have bromination at the carbon bearing the -COOH group, and this is followed by decarboxylation to give o-bromophenol. Phenols, being highly activating group, undergo bromination at all three available positions, giving 2,4,6-Tribromophenol.

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Answer 2

Answer:

When salicylic acid is treated with the bromine water it leads to the formation of 2,4,6 - tribromophenol.

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