what is formula for a3 - b3?
Answers
Answered by
3
Answer:
take care dude
Step-by-step explanation:
We can derive the above using identity (a−b)3
(a−b)3=a3−3a2b+3ab2−b3(a−b)3=a3−3a2b+3ab2−b3
(a−b)3=a3−3ab(a−b)−b3(a−b)3=a3−3ab(a−b)−b3
(a−b)3+3ab(a−b)=a3−b3(a−b)3+3ab(a−b)=a3−b3
(a−b)[(a−b)2+3ab]=a3−b3(a−b)[(a−b)2+3ab]=a3−b3
(a−b)[a2−2ab+b2+3ab]=a3−b3(a−b)[a2−2ab+b2+3ab]=a3−b3
(a−b)[a2+ab+b2]=a3−b3
Answered by
1
Answer:
a3 – b3 = (a – b) (a2 + ab + b2 ).
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