what is formula of bisection of pair of lines
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Step-by-step explanation:
Let P(α, ß) be any point on one of bisectors. ax2 + 2hxy + by2 = 0 and one of the lines given by ax2 + 2hxy+ by2 + K(x2 + y2) = 0 is equal to the angle between the other two lines of the system.
Solution: Let L1 and L2 be one pair and L3 and L4 be the other pair of lines.
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Answer:
a1x+b1y+c1√a21+b21 = + a2x+b2y+c2√a22+b22, which is the required bisector of the angle containing the origin. Note: The bisector of the angle containing the origin means the bisector of that angle between the two straight lines which contains the origin within it.
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