Math, asked by vk7489573, 5 months ago

what is formula of cos 4x ka
plz write here ....?​

Answers

Answered by Harsithaa
1

Answer:

2cos^2(2x) - 1 ——(1) cos 4x = cos 2(2x) = 1- sin^2 (2x) ——(2) cos 4x = cos^2(2x) - sin^2 (2x) ———(3) again the above threeformulas can be written as simplified form using formula cos 2x = 2cos^2 x -1 / 1- 2sin^2 x / cos^2 x - sin^2 x as per requirement.

Answered by anshvohra24
1

Step-by-step explanation:

cos 4x = cos 2(2x)= 2cos^2(2x) - 1 ——(1) cos 4x = cos 2(2x) = 1- sin^2 (2x) ——(2) cos 4x = cos^2(2x) - sin^2 (2x) ———(3) again the above threeformulas can be written as simplified form using formula cos 2x = 2cos^2 x -1 / 1- 2sin^2 x / cos^2 x - sin^2 x as per requirement.

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