what is formulla of 1+sinx
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we know, Sin²X + Cos²X = 1
=> 1- Sin²X = Cos²X
=> (1+SinX) (1- SinX) = Cos²X
=> (1+SinX) = Cos²X / (1-SinX) ………..(1)
OR, 1+ SinX = 1+ (1/CosecX )
=>( 1+SinX) = (CosecX +1)/CosecX ……(2)
OR, (1+SinX) = 1+ √(1-Cos²X) ………(3)
OR, (1+SinX) = 1+(1/√(Cot²X+1) …….(4)
=> 1- Sin²X = Cos²X
=> (1+SinX) (1- SinX) = Cos²X
=> (1+SinX) = Cos²X / (1-SinX) ………..(1)
OR, 1+ SinX = 1+ (1/CosecX )
=>( 1+SinX) = (CosecX +1)/CosecX ……(2)
OR, (1+SinX) = 1+ √(1-Cos²X) ………(3)
OR, (1+SinX) = 1+(1/√(Cot²X+1) …….(4)
Answered by
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heya friend ✋✋
here's your answer⬇⬇
FORMULAS...
❇sin^2A + cos^2A = 1
❇ sinA=1/cosecA
HOPE IT HELPS U ^_^
here's your answer⬇⬇
FORMULAS...
❇sin^2A + cos^2A = 1
❇ sinA=1/cosecA
HOPE IT HELPS U ^_^
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