Question

What is g’(x)? Calculus derivative help

Answer 1

Answer:

$\underline{\huge{\texttt{12}}}$

Step-by-step explanation:

$h'(x) = [f(x)\times g(x)] '=f'(x )g(x) + f(x)g'(x)\\h'(1) = [f(1)\times g(1)] '=f '(1)g(1) + f(1)g'(1)\\From\: the\: table\: f '(1)= -3, g(1)=2, f(1)= 3, g'(1) =6\\h'(1) = f '(1)g(1) + f(1)g'(1) = -3\times2 + 3\times6= - 6+ 18 = 12$

Answer 2

Answer:

Step-by-step explanation:

h'(x) = f'(x)g(x) + f(x)g'(x)

h'(1) = f'(1)g(1) + f(1)g'(1)

= (- 3) × 2 + 3 × 6

= - 6 + 18

= 12.