Physics, asked by TheLoneWolf888, 1 year ago

What is $\gamma$$\rho$ mixing?

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Answered by rockyak4745
0
We study the effect of rho^0-gamma mixing in e^+e^- to pi^+pi^- and its relevance for the comparison of the square modulus of the pion from-factor |F^(e)_pi|^2, as measured in e^+e^- annihilation experiments, and |F^(tau)_pi|^2 the corresponding quantity obtained after accounting for known isospin breaking effects by an isospin rotation from the tau-decay spectra. After correcting the tau data for the missing rho-gamma mixing contribution, besides the other known isospin symmetry violating corrections, the pi pi I=1 part of the hadronic vacuum polarization contribution to the muon g-2 are fully compatible between tau based and e^+e^- based evaluations. tau data thus confirm result obtained with e^+e^- data. Our evaluation based on all e^+e^- data including more recent BaBar and KLOE data yields a_mu^(had)=690.75(4.72) x 10^{-10} (e^+e^- based), while including tau data we find a_mu^(had)=690.96(4.65) X 10^{-10} (e^+e^-+tau based). This backs the ~3 sigma deviation between theory and experiment. For the tau di-pion branching fraction we find B^{CVC}_{pi pi^0}=25.20 \pm0.0.17\pm0.28 from e^+e^-+CVC, while B_{pi pi^0}=25.34\pm0.0.06\pm0.08 is evaluated directly from the tau spectra.
Answered by SnehaG
2
gamma rho mixing is the mixing of radio active neutral element with a resistivity term usually determines the mutual sharing incrudently.this also is respinsible for catenation and tetravalency
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