what is general 5 digit number using 9, 8, 7 with 8 at hundreds place.
Answers
There can be multiple answers to this question. Some of them are as follows: 97898, 87899, 79889, 98897, 89877 ...
Given,
Three digits 9, 8, 7.
To Find,
A general 5 digit number using 9, 8, 7 with 8 at hundreds places.
Solution,
Five-digit numbers are numbers on the number line starting from 10000 and going up to 99999.
We have to form a five-digit number using 3 digits while having 8 in the hundreds place.
The ten-thousands places can be any of the three digits (9, 8, 7).
Thousands places can be any of the three digits (9, 8, 7).
Hundreds places will only contain 8 as their digit.
Tens place can be any of the three digits (9, 8, 7).
Ones place can be any of the three digits (9, 8, 7).
Thus total possibilities are 3 × 3 × 1 × 3 × 3
∴ 81 general numbers can be formed using these digits having 8 at hundreds place.
Answer:
There are 81 general numbersthat can be formed
Step-by-step explanation:
We have to form a five-digit number using only 3 digits while having 8 in the hundreds place.
The ten-thousands places can be occupied by any of the three digits (9, 8, 7).
Thousands places can be occupied by any of the three digits (9, 8, 7).
Hundreds places will only contain 8 as their digit.
Tens place can be occupied by any of the three digits (9, 8, 7).
Ones place can be occupied by any of the three digits (9, 8, 7).
Thus total number of possibilities are 3 × 3 × 1 × 3 × 3
∴ 81 general numbers can be formed using these digits having 8 at hundreds place.