What is going in tali ban in afginastan
Answers
Explanation:
Solution
\Large{\underline{\mathfrak{\bf{\red{Given}}}}}
Given
\mapsto\sf{\green{\:(a^2+\dfrac{1}{a^2})\:=\:27}}↦(a
2
+
a
2
1
)=27
\Large{\underline{\mathfrak{\bf{\red{Find}}}}}
Find
\mapsto\sf{\green{\:(a+\dfrac{1}{a})\:=\:?}}↦(a+
a
1
)=?
\Large{\underline{\underline{\mathfrak{\bf{\pink{Explanation}}}}}}
Explanation
we know,
\bigstar\sf{\green{\:(x+y)^2\:=\:(x^2+y^2+2xy)}}★(x+y)
2
=(x
2
+y
2
+2xy)
So,
\begin{gathered}\mapsto\sf{\green{\:(a+\dfrac{1}{a})^2\:=\:(a^2+\dfrac{1}{a^2}+2.\red{\cancel{a}}.\dfrac{1}{\red{\cancel{a}}})}} \\ \\ \mapsto\sf{\:(a+\dfrac{1}{a})\:=\:\sqrt{(a^2+\dfrac{1}{a^2})+2}} \\ \\ \mapsto\sf{\:(a+\dfrac{1}{a})\:=\:\sqrt{(27)+2}} \\ \\ \mapsto\sf{\pink{\:(a+\dfrac{1}{a})\:=\:\sqrt{29}}}\end{gathered}
↦(a+
a
1
)
2
=(a
2
+
a
2
1
+2.
a
.
a
1
)
↦(a+
a
1
)=
(a
2
+
a
2
1
)+2
↦(a+
a
1
)=
(27)+2
↦(a+
a
1
)=
29
\Large{\underline{\mathfrak{\bf{\red{Thus}}}}}
Thus
\mapsto{\red{\boxed{\sf{\orange{\:Value\:of\:(a+\dfrac{1}{a})\:=\:\sqrt{29}}}}}}↦
Valueof(a+
a
1
)=
29
Some Important Formula
★(a+b)^2=(a^2+b^2+2ab)
★(a-b)^2 = (a^2+b^2-2ab)
★(a-b)(a+b)= (a^2-b^2)
★(a+b)^3 = a^3+b^3+3ab(a+b)
★(a-b)^3 = a^3-b^3+3ab(a-b)
★(a^3-b^3)=(a-b)(a^2+b^2+ab)
★(a^3+b^3)=(a-b)(a^2+b^2-ab)