what is greatest possible digit to write in the blank of the number _6724 so that the number formed is divisible by 3?
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Answer:
the required digits are 2 and 8.
Step-by-step explanation:
We will be using the concepts of divisibility by 3 to solve this.
A number is divisible by 3 if the sum of all digits in the number is also divisible by 3.
(a) ___ 6724
Sum of the digits = 4 + 2 + 7 + 6 = 19
Thus, The smallest digit to be placed is blank space = 2.
Then the sum = 19 + 2 = 21, which is divisible by 3.
The greatest digit to be placed in blank space = 8.
Then, the sum = 19 + 8 = 27, which is divisible by 3
Therefore, the required digits are 2 and 8.
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