Question

what is greatest possible of a vessel that can b used to measure exactly the volume of milk in cans of 80litres 100 litres and 120​

Answer 1

ans of this word problem is 20

Answer 2

Greatest possible of a vessel is $\textrm{20 liter}$

Step-by-step explanation:

We have to find the greatest possible quantity of a vessel can measure all given quantities so we will take the greatest common divisors of given quantities

               $80 = 2^{4} \times 5$

               $100 = 2^{2} \times 5^{2}$

               $120 = 2^{3} \times 5 \times 3$

               $GCD = 2^{2}\times 5$

           ⇒   $GCD = \textrm{20 liter}$