Chemistry, asked by maitrimayuribej, 3 months ago

what is h÷4π in Heisenberg uncertainty principle​

Answers

Answered by rohitmishra73
1

Answer:

It simply states that a particle behaves both as a wave and a particle and therefore cannot have both a definite momentum and position. 3.) Uncertainty principle: ΔxΔp≥h/4Π Can be written (x)(m)(v)(%)=h/4Π (position)(mass of electron)(velocity)(percent accuracy)=(Plank's Constant)/4Π

Answered by krishna56789
0

delta x * m* delta v≥h/4pie

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