Question

What is h(t(x)) if h(x)=2x2−3x+1 and t(x)=x2−1?

Answer 1

Answer:

5/3 and 1/2

Step-by-step explanation:

h(x) =2×2 - 3x + 1

0= 4- 3x +1

3x=4+1

x= 5/3

t(x) = 2x -1

0=2x-1

1=2x

1/2=x