What is Hawking Hartle vacuum state and why does the following Euclidean path integral gives the wave functional of it?
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Answered by
1
Hey mate ^_^
where W[ψ]=12∫ψD^ψW[ψ]=12∫ψD^ψ is the action of the quantum field ψψ, and the path integral is defined over field configuration on the half-period Euclidean instanton defined by the metric:
#Be Brainly❤️
where W[ψ]=12∫ψD^ψW[ψ]=12∫ψD^ψ is the action of the quantum field ψψ, and the path integral is defined over field configuration on the half-period Euclidean instanton defined by the metric:
#Be Brainly❤️
Answered by
5
Hello mate here is your answer.
Where W[ψ]=12∫ψD^ψW[ψ]=12∫ψD^ψ is the action of the quantum field ψψ, and the path integral is defined over field configuration on the half-period Euclidean instanton defined by the metric:
ds2=ρ2dϕ2+dρ2+γijdθidθjds2=ρ2dϕ2+dρ2+γijdθidθj
, where ϕϕ varies from 0 to 2π2π. Then the author claims that the path integral is the Hartle Hawking vacuum state.
Hope it helps you.
Where W[ψ]=12∫ψD^ψW[ψ]=12∫ψD^ψ is the action of the quantum field ψψ, and the path integral is defined over field configuration on the half-period Euclidean instanton defined by the metric:
ds2=ρ2dϕ2+dρ2+γijdθidθjds2=ρ2dϕ2+dρ2+γijdθidθj
, where ϕϕ varies from 0 to 2π2π. Then the author claims that the path integral is the Hartle Hawking vacuum state.
Hope it helps you.
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