Question

what. is HCF of 1 upon 5 2 upon 7 and 3 upon 11​

Answer 1

Answer:

HCF will be

$1 \div 385$

Answer 2

The correct answer is  option (a) 1/385

Given:

$\frac{1}{5}$, $\frac{2}{7}$ and $\frac{3}{11}$  

To find:

HCF of $\frac{1}{5}$, $\frac{2}{7}$ and $\frac{3}{11}$  

Solution:

• HCF means Highest Common Factor

• HCF of two numbers is the highest factor which can divide the given numbers, evenly.

• For fractions like $\frac{a}{e}$, $\frac{b}{f}$ and $\frac{c}{g}$ the HCF is given by  

                    HCF(a, b, c) / LCM(e,f,g)

Given fractions  $\frac{1}{5}$, $\frac{2}{7}$ and $\frac{3}{11}$

HCF ( $\frac{1}{5}$, $\frac{2}{7}$, $\frac{3}{11}$ ) = HCF(1,2,3) / LCM(5,7,11)

⇒  HCF(1,2,3) = 1

⇒  LCM(5,7,11) = 5 × 7× 11 = 385  

HCF ( $\frac{1}{5}$, $\frac{2}{7}$, $\frac{3}{11}$ ) =  1/385

The correct answer is  option (a) 1/385

#SPJ2