Chemistry, asked by nihalmishra55, 11 months ago

what is hess law of constants heat summation ? give an example to explaine the law​

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Answered by Anonymous
13
 \textsf{\underline {\Large {Hess's Law of Constant Heat Summation :}}}

 \textsf{\underline {The basis of Hess's law is that enthalpy is a state function.}}

According to this law, the change in enthalpy remains constant whether the process is carried out in one step or in more than one step.

 \textsf{\underline {\large{Applications of Hess Law}}} :

1. Calculation of enthalpy of formation.

2. Calculation of  \mathsf{_{c}H} .

3. Calculation of Enthalpy of reaction.

4. Calculation of enthalpy of allotropic transformation.

\textsf{\large{\underline {Example}}} :

Let 's consider this law by the formation of  \mathsf{CO_2} and  \mathsf{O_2}  

 \mathsf{\underline {Way\: 1}} :  \mathsf{C(s) \:+\:O_2(g)\:{\rightarrow{CO_2(g)}}}

 \Delta{\mathsf{_{r}{H}^{\circ}\:=\:-393.5\:kJ}}  

 \mathsf{\underline {Way \:2}} :  \mathsf{C(s) \:+\:{\dfrac{1}{2}O_2(g)\:{\rightarrow{CO(g)}}}}

 \Delta{\mathsf{_{r}H_{1}^{\circ}\:=\:-110.5\:kJ}}  

 \mathsf{CO(g) \:+\:{\dfrac{1}{2}O_2(g)\:{\rightarrow{CO_2(g)}}}}

 \Delta{\mathsf{_{r}H_{2} ^{\circ}\:=\:-283.0\:kJ}}  

 \boxed{\mathsf{C(s) \:+\:O_2(g)\:{\rightarrow{CO_2(g)}}}}

 \Delta{\mathsf{_{r}{H}^{\circ}\:=\:-393.5\:kJ}}  

➡️  \boxed{\Delta{\mathsf{H\:=\:{\Delta{H_1}\:+\:{\Delta{H_2}}}}}}
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nihalmishra55: so much thank you
Anonymous: Happy to help.
Answered by ElegantDoll
1

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❤.Hess law : "The total heat change in a reaction is the same whether the chemical reaction takes place in a single step or in several steps".

❤.It is based on the I law of thermodynamics .

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