What is horizontal component of 200 N force which is directed from (0,3,0) to (0,0,4)
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If the force at an angle of 30° to horizon is p its vertical.component is p*Sin 30°
As this vertical component of the force is given as 200 N,
p*Sin 30°= 200 N or
p* 1/2 = 200 N , or p = 400 N
The horizontal component of 400 N at 30° to horizon is 400* Cos 30° , or 400*√3/2 , or
200√3 N or 346.41 N
Hope it help
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