What is √, if n is not a perfect square number?
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so, √n = a/b where a and b are integers and b is not equation to zero . but this contradict the fact that a and b are co- prime.
Step-by-step explanation:
so, √n = a/b where a and b are integers and b is not equation to zero . but this contradict the fact that a and b are co- prime
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