what is In a Brahmas press a force of 10 kg wt, is applied on a piston of area of cross section 5 em Calculate the upward thrust exerted by the piston of area of cross section 50 cm ??
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Step-by-step explanation:
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Correct Question:
In a Brahmas press a force of 10 kg wt, is applied on a piston of area of cross section 5 cm². Calculate the upward thrust exerted by the piston of area of cross section 50 cm²?
Answer:
100 kg wt
Step-by-step explanation:
Given that in a Brahmas press a force of 10 kg wt, is applied on a piston of area of cross section 5 cm². Here, the force is 10 kg wt and area of cross section or area is 5 cm.
Pressure is defined as force per unit area. And it is a scaler quantity.
Pressure = Force/Area
Substitute the values,
Pressure = 10/5 kg wt/cm²
Pressure = 2 kg wt/cm²
Now, in second case we need to find out the upthrust force if the area of cross section is 50 cm². From above pressure is 2 kg wt/cm². Substitute the values to get the value of force.
Force (upthrust) = 50 cm² × 2 kg wt/cm²
Force (upthrust) = 100 kg wt
Therefore, the upward thrust exerted by the piston of area of cross section 50 cm² is 100 kg wt.
# Method 2)
Assume a piston having one end B of area of cross section A and other of B' of cross section area A'. When we apply force at side B; B' will lift up and vice-versa. As per Pascal's law we can say that B/A = B'/A' (as the pressure inside the fluid is transmitted equally)
B = (B' × A)/A' (here, A is 50 cm², B' is 10 kg wt and A' is 5 cm²)
B = (50 × 10)/5
B = 10 × 10
B = 100 kg wt
Therefore, the upward thrust exerted by the piston of area of cross section 50 cm² is 100 kg wt.