Question

What is in math 3+jk+k’3 when j = 2 and k=6

Answer 1

Answer:

3+jk+k^6

j=2 & k=6

substituting the values, we have

= 3+2(6)+6^3

= 3+12+216

= 231

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

3+jk+k’3 when j = 2 and k=6

substituting values we get-

3+2x6+6³=3+12+216=216+15=231

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