What is infinite minus infinite?
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Answered by
7
If we assume
∞ - ∞ = 0
∞ - ∞ + 1 = 0 + 1
Since ∞ + 1 = ∞ and 0 + 1 = 1, then we are going to simplify both parts of the equation:
∞ - ∞ = 1 (but not possible)
Let's prove this another way. Again, assuming this is true:
∞ - ∞ = 0
Since we know that ∞ = ∞ + ∞, then we get:
(∞ + ∞) - ∞ = 0
∞ + ∞ - ∞ = 0
Since we assumed ∞ - ∞ = 0, then
∞ + 0 = 0
∞ = 0
This is obviously incorrect, so :
∞ - ∞ ≠ 0
∴∞ - ∞ = undefined
Let's say :
∞ - ∞ = n
Since we know that ∞ = ∞ + ∞, we get:
(∞ + ∞) - ∞ = n
Which is equal to:
∞ + ∞ - ∞ = n
Since we already assumed ∞ - ∞ = n,
∴∞ + n = n
∞ = 0
So
∞ - ∞ ≠ n
Specifically, we can again conclude that
∞ - ∞ = undefined
∞ - ∞ = 0
∞ - ∞ + 1 = 0 + 1
Since ∞ + 1 = ∞ and 0 + 1 = 1, then we are going to simplify both parts of the equation:
∞ - ∞ = 1 (but not possible)
Let's prove this another way. Again, assuming this is true:
∞ - ∞ = 0
Since we know that ∞ = ∞ + ∞, then we get:
(∞ + ∞) - ∞ = 0
∞ + ∞ - ∞ = 0
Since we assumed ∞ - ∞ = 0, then
∞ + 0 = 0
∞ = 0
This is obviously incorrect, so :
∞ - ∞ ≠ 0
∴∞ - ∞ = undefined
Let's say :
∞ - ∞ = n
Since we know that ∞ = ∞ + ∞, we get:
(∞ + ∞) - ∞ = n
Which is equal to:
∞ + ∞ - ∞ = n
Since we already assumed ∞ - ∞ = n,
∴∞ + n = n
∞ = 0
So
∞ - ∞ ≠ n
Specifically, we can again conclude that
∞ - ∞ = undefined
theAM:
Amazing answer buddy
Answered by
4
Suppose I have infinite number of rooms numbered as 1, 2, 3 and so on
If I give all the odd numbered rooms, then also i have infinite number of rooms.
we conclude that ∞-∞=∞
if i give all of them, then i will have 0
∞-∞=0
if i give all the room except for the first 10, then i will have 10 rooms
so ∞-∞=10
since ∞≠0≠10
so ∞-∞ is not defined
If I give all the odd numbered rooms, then also i have infinite number of rooms.
we conclude that ∞-∞=∞
if i give all of them, then i will have 0
∞-∞=0
if i give all the room except for the first 10, then i will have 10 rooms
so ∞-∞=10
since ∞≠0≠10
so ∞-∞ is not defined
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