what is integral of sin 3x
Answers
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the answer is.... -cos3x/3
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The answer is−cos3x3+C
Explanation:
Explanation:
The integral of sinθ is −cosθ
You can use the substitution, u=3x the du=3dx
∫sin3xdx=∫sinudu3=−cosu3=−cos3x3+
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