what is integration of 1/logx
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let log x=t , x=e^t
when we diff...it..
1/x dx=dt
integration of 1/logx dx
integration of e^t/t dt = infinity or E(i) x+ c
E(i) logx+c
it is your answer.....
integration of e^t/t dt
=e^t/t( 1+1/x+2/x^2+6/x^3+24/x^4+......)
when we diff...it..
1/x dx=dt
integration of 1/logx dx
integration of e^t/t dt = infinity or E(i) x+ c
E(i) logx+c
it is your answer.....
integration of e^t/t dt
=e^t/t( 1+1/x+2/x^2+6/x^3+24/x^4+......)
silu12:
hope it will help you
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