what is integration of 1-x
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Integration of [(1-x) dx]
= x - (1/2)(x^2) + c,
where c is the integral constant.
I HOPE THAT THIS HELPS YOU.
Integration of [(1-x) dx]
= x - (1/2)(x^2) + c,
where c is the integral constant.
I HOPE THAT THIS HELPS YOU.
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