Question

what is its answer
2sin26\cos64-4tan65\cot25+cosec70\sec20​

Answer 1

Answer:

‐1

Step-by-step explanation:

2cos(90‐26)/cos64 ‐ 4tan65/tan(90‐25) +sec(90‐70)/sec20

=2cos64/cos64 ‐ 4tan65/tan65 + sec20/sec20

=2‐4+1

=‐1

Answer 2

Answer:

Step-by-step explanation:

2sin26°/cos64° - 4tan65°/cot25° + cosec70°/sec20°

=2sin[90°-64°]/cos64° -4tan[90°-25°]/cot25° +cosec[90°-20°]/sec20°

=2cos64°/cos64° -4cot25°/cot25° +sec20°/sec20°           {sin[90°-α]=cosα}

                                                                                              {tan[90°-α]=cotα}

                                                                                         {cosec[90°-α]=sec α}

=2-4+1

=3-4

=-1