what is its derivative....
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taking log on both sids....
ylogx=(x-y) loge [loge=1]
logx.dy/dx+y.1/x=1-dy/dx
dy/dx (logx+1)=1-y/x
dy/dx=1-y/x /(logx+1)
ylogx=(x-y) loge [loge=1]
logx.dy/dx+y.1/x=1-dy/dx
dy/dx (logx+1)=1-y/x
dy/dx=1-y/x /(logx+1)
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