Question

what is K. E of one molecule of N2​

Answer 1

Answer:

Total kinetic energy=$\frac{5}{2} nRT$

Number of moles (n)=1

Universal gas constant(R)=2 cal/mol.K

Temperature consider is T=$27^{0} C=(27+273)K=300 K$

Now, Total kinetic energy=5/2*1*2*300

                                          =5*300

                                          =1500cal