Physics, asked by Irfan1729, 11 months ago

what is Laplace correction?????​

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Answered by SharmaShivam
6

\mathcal{SPEED\:\:OF\:\:SOUND}

On the basis of observations, Newton obtained a formula for speed of sound in air as

\sf{v=\sqrt{\dfrac{P}{\rho}}}

where P is the isothermal elasticity of the air.

By Newton's formula the speed of sound at one atmosphere is

\sf{V=\sqrt{\dfrac{1.013\times\:10^5}{1.29}}\cong\:280m/s}

This value is less than experimental value of 332 m/s. Hence Newton's formula requires some correction, which was made by Laplace.

\mathcal{LAPLACE'S\:\:CORRECTION}

Laplace pointed out that when sound propagates in air the heat of the medium remains constant instead of its temperature. So he replaced isothermal elasticity by adiabatic elasticity \sf{B_{ad}}. The corrected formula is

\sf{v=\sqrt{\dfrac{B_{ad}}{\rho}}}

For adiabatic change, \sf{PV^{\gamma}=constant}

Differentiating both sides, we get

\sf{P\left(\gamma\:V^{\gamma-1}\right)dV+V^{\gamma}dP=0}

\implies\sf{\gamma\:PdV+VdP=0}

\sf{\dfrac{dp}{\left(\dfrac{-dV}{V}\right)}=\gamma\:P}

We have \sf{\dfrac{dp}{\left(\dfrac{-dV}{V}\right)}=B_{ad}}

\sf{\therefore\:B_{ad}=\gamma\:P}

where \sf{\gamma=\dfrac{C_p}{C_v}} is the ratio of specific heats. Hence Laplace's formula for speed of sound in air (gas) is

\sf{v=\sqrt{\dfrac{\gamma\:P}{\rho}}}

For air \gamma=\dfrac{7}{4}, so the speed of sound in air at STP will be

\sf{v=\sqrt{\gamma}{\dfrac{P}{\rho}}=\sqrt{\dfrac{7}{4}}\times\:280=332m/s}

This value is in very close agreement with the experimental value.

Answered by vidhipatel129
1

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