what is last digit of 2power4+5power2021+3power107
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Step-by-step explanation:
What is last digit of this number [math]2^{234567923}[/math]?
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Lets examine some "Last digits" of various powers of 2.
[math]2^1[/math] = 2 [math]2^2[/math] = 4 [math]2^3[/math] = 8 [math]2^4[/math] = 16
[math]2^5[/math] = 32 [math]2^6[/math] = 64 [math]2^7[/math] = 128 [math]2^8[/math] = 256
Do you see the pattern? All you have to do is divide the exponent by 4 and get the remainder.
If the remainder is 0, last digit is 6
If the remainder is 1, last digit is 2
If the remainder is 2, last digit is 4
If the remainder is 3, last digit is 8
So given this set of rules, we divide 234567923 by 4 and get a remainder of 3. Therefore,
Final Answer: 8
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