Question

What is length of the diagonal of a square whoes sode is 8 cm?

Answer 1

We know that in a square, all angles are right angles.
Therefore, two adjacent sides will make a right angled triangle with one diagonal.
Therefore,
$( {side)}^{2} + (side) {}^{2} = (diagonal) {}^{2}$
The measure of one side is 8 cm.

${8}^{2} + {8}^{2} = (diagonal) {}^{2}$
$64 + 64 = (diagonal) {}^{2}$
$2 \times 64 = (diagonal) {}^{2}$
$diagonal = 8 \sqrt{2}$
Therefore, the measure of the diagonal of a square with sides measuring 8 cm will be 8√2 cm.

There is also a common formula to find the measure of diagonal of square,
$diagonal = \sqrt{2} \times side \: measure$
Thank you :) <3

Answer 2

Answer:

Step-by-step explanation: