Question

What is likely to be orbit number for a circular orbit of diameter 20 nm of the hydrogen atom?

Answer 1

Answer:

14 will likely to be the orbit number for a circular orbit.

Explanation:

                            Given Data :

Diameter = d = 20nm

radius = r = 10nm

r of nth shell= 0.539 X n X n

1nm = 0.1A= 0.1e -10

As,

0.539A = 0.0539 nm

                              Solution :

r = r of nth shell

10 = 0.0539 x n x n

n x n = 185.528

By taking its square root, we will get

n = 13.62

The orbit can't be 13.62. So, it's 14.( rounded off value)

Answer 2

Dear Student,

● Answer -

Orbit number = 14

◆ Explaination -

# Given -

d = 20 nm

r = 10 nm = 100 A°

# Solution -

Bohr's radius of H-atom (in A°) is calculated by formula -

r = 0.529 n^2

100 = 0.529 n^2

n^2 = 100 / 0.529

n^2 = 189

Taking square root,

n = √189

n = 13.75

Rounding off, we can say that principal quantum number of given orbit is 14.

Thanks dear.