Question

What is likely to be principal quantum number for the circular orbit of diameter 20.6 NM of the hydrogen atom if we ask him for Orbit to be the same as the represented by the principal quantum number is

Answer 1

Answer:

14 will likely to be the orbit number for a circular orbit.

Explanation:

Given Data :

Diameter = d = 20nm

radius = r = 10nm

r of nth shell= 0.539 X n X n

1nm = 0.1A= 0.1e -10

As,

0.539A = 0.0539 nm

Solution :

r = r of nth shell

10 = 0.0539 x n x n

n x n = 185.528

By taking its square root, we will get

n = 13.62

The orbit can't be 13.62. So, it's 14.( rounded off value)