Question

what is limiting reagent when 25g of N2 reacts with 15g of H2 to yield ammonia​

Answer 1

Answer:

N2

Explanation:

N2+3H2=2NH3

$moles \: of \: n2 \div 1 = moles \: of \: h2 \times \div 3 = moles \: of \: nh3 \div 2$

which have lowest ratio that will be the liming reagent

moles of N2÷1=25/28

moles of H2÷3=15/2×3=15/6

moles of N2/1 have lowest ratio so N2 is limiting agent