Question

what is
log 5+ log 8- log 4​

Answer 1

Step-by-step explanation:

I'm assuming that the default base of each log is 10.

log%2810%2C%288%29%29%2Blog%2810%2C%285%29%29-log%2810%2C%284%29%29 Start with the given expression.

log%2810%2C%288%2A5%29%29-log%2810%2C%284%29%29 Combine the logs using the identity log%28b%2C%28A%29%29%2Blog%28b%2C%28B%29%29=log%28b%2C%28A%2AB%29%29

log%2810%2C%2840%29%29-log%2810%2C%284%29%29 Multiply

 

log%2810%2C%2840%2F4%29%29 Combine the logs using the identity log%28b%2C%28A%29%29-log%28b%2C%28B%29%29=log%28b%2C%28A%2FB%29%29

log%2810%2C%2810%29%29 Reduce

1 Evaluate the log base 10 of 10 to get 1

So log%2810%2C%288%29%29%2Blog%2810%2C%285%29%29-log%2810%2C%284%29%29=1

Answer 2

Answer:

its a very simple dude logm+logn=logm×n log 5×8-log4=log40-log 4=log 40/4(log m-n=log m/n).......... log40/4=log 10=1 bcz yhe value of log 10 is 1 so the answer is 1